Setting Values in an Multidimensional numpy Array with Indexes

Question

i am searching for an elegant and efficient way to initialize a 3dimensional numpy array that is all zeros but for a specific row. E.g.

empty = np.zeros((3,3,2))
row_indexes = np.array([1,1,0])
replacement = np.array([[1,2][3,5][5,6]])
# intended outcome:
[[[0 0]
  [1 2]
  [0 0]]
 [[0 0]
  [3 5]
  [0 0]]
 [[5 6]
  [0 0]
  [0 0]]]

I could iterate over each two dimensional array along the zero dimension, but that seems inelegant. Is there an efficient oneliner for this problem?

Mechanic Pig · Accepted Answer · 2022-10-04 13:49:40Z

2

The row_indexes is used as the second dimension here. Just build the index of the corresponding first dimension, and then directly assign values:

>>> empty[np.arange(len(empty)), row_indexes] = replacement
>>> empty
array([[[0., 0.],
        [1., 2.],
        [0., 0.]],

       [[0., 0.],
        [3., 5.],
        [0., 0.]],

       [[5., 6.],
        [0., 0.],
        [0., 0.]]])

answered Oct 4, 2022 at 13:49

Mechanic Pig

7,7813 gold badges17 silver badges35 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Setting Values in an Multidimensional numpy Array with Indexes

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related