Spring REST API - Return HTTP status from 3rd party

You have to create advice for your rest controller with @RestControllerAdvice annotation this will catch your exceptions and then you can handle all exceptions in this advice. Just debug and see what type of exceptions thrown from 3rd party and handle all of them in advice. Here is the sample

@RestControllerAdvice
public class ProductExceptionHandler {

@ExceptionHandler(ConstraintViolationException.class)
public ResponseEntity<ErrorMessage> handleInvalidArgument(ConstraintViolationException ex, WebRequest webRequest) {
    return generateErrorMessage(ex, webRequest);
}

private ResponseEntity<ErrorMessage> generateErrorMessage(Throwable ex, WebRequest request){
    ErrorMessage errorMessage = new ErrorMessage.ErrorMessageBuilder()
            .statusCode(HttpStatus.BAD_REQUEST.value())
            .timeStamp(DateTimeFormatter.ofPattern("yyyy/MM/dd HH:mm:ss").format(LocalDateTime.now()))
            .message(ex.getMessage())
            .description(request.getDescription(false))
            .build();
    return new ResponseEntity<>(errorMessage, HttpStatus.BAD_REQUEST);
}

}