JSON and PHP arrays

Question

json_encode(array(
    array(0 => "431.940054495913"),
    array(1 => "431.940054495913"),
));

Is rendered like this:

[
    ["431.940054495913"],
    {"1":"431.940054495913"}
]

Why are the two arrays rendered differently ?

Difficult to understand what is being asked. Everything looks normal to me. — Layke
– Layke, Commented Sep 8, 2011 at 11:10
He wants to know why the elements with key '0' and key '1' are different when converted to JSON — Paul Dixon
– Paul Dixon, Commented Sep 8, 2011 at 11:12

Arnaud Le Blanc · Accepted Answer · 2011-09-10 18:05:01Z

17

Any PHP array that can be rendered as a JSON array will be rendered as a JSON array: Any PHP array having only sequential numeric keys starting from 0 will be rendered as a JSON array.

This is the case for the first array: array(0 => "431.940054495913").

How to fix this

The JSON_FORCE_OBJECT flag will render all PHP arrays as JSON objects

json_encode(array(0 => "431.940054495913"), JSON_FORCE_OBJECT);
// {"0": "431.940054495913"}

json_encode(array(0 => "431.940054495913"));
// ["431.940054495913"]

Alternatively, you could convert your PHP array to a PHP object:
```
json_encode( (object) array(0 => "431.940054495913"));
// {"0": "431.940054495913"}
```
(if you don't want to render every array as object or if you don't have JSON_FORCE_OBJECT)

edited Sep 10, 2011 at 18:05

answered Sep 8, 2011 at 11:10

Arnaud Le Blanc

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1 Comment

Fuzzy Over a year ago

Thanks. Tried both and they both fix the issue. Good to know :)

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