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Workarounds for JavaScript parseInt octal bug
How to parseInt a string with leading 0
document.write(parseInt("07"));
Produces "7"
document.write(parseInt("08"));
Produces "0"
This is producing problems for me (sorry for this babble, I have to or I can't submit the question). Anyone know why it's being stupid or if there is a better function?
If you argument begins with 0, it will be parsed as octal, and 08 is not a valid octal number. Provide a second argument 10 which specifies the radix - a base 10 number.
document.write(parseInt("08", 10));
use this modification
parseInt("08",10);
rules for parseInt(string, radix)
If the radix parameter is omitted, JavaScript assumes the following:
You want parseInt('08', 10) to tell it to parse as a decimal.
You just using input parameters of that function in a bit wrong way. Check this for more info. Basically :
The parseInt() function parses a string and returns an integer.
The radix parameter is used to specify which numeral system to be used, for example, a radix of 16 (hexadecimal) indicates that the number in the string should be parsed from a hexadecimal number to a decimal number.
If the radix parameter is omitted, JavaScript assumes the following:
- If the string begins with "0x", the radix is 16 (hexadecimal)
- If the string begins with "0", the radix is 8 (octal). This feature is deprecated
- If the string begins with any other value, the radix is 10 (decimal)
So 07 and 08 is parsed into octal . That's why 07 is 7 and 08 is 0 (it is rounded to closest)
Try this :
parseInt('08', 10)
it will produce 8
