looping through two array to replace one value in array for specific match

Question

I've two arrays like below

flag: true
firstName: "user1"
lastName: "usr1"

flag: true
firstName: "user2"
lastName: "usr2"

flag: true
firstName: "user3"
lastName: "usr3"

And the other one like below

"user1"
"user2"

My intention is, the second array value matches the first array with firstname then needs to override flag with false.

I'm expecting a result like

flag: false
firstName: "user1"
lastName: "usr1"

flag: false
firstName: "user2"
lastName: "usr2"

flag: true
firstName: "user3"
lastName: "usr3"

Note: If firstname is not matched. I don't want to change the flag value. –

Any good way to achieve this in react, Thanks

Oki · Accepted Answer · 2022-07-27 15:45:11Z

2

consider:

array 1 = users

array 2 = userNames

Then: This one will change the flag to true if user.firstName exist in userNames, else to false

users.map((user) => ({...user, flag: !userNames.includes(user.firstName)}))

This will return you the new array

If you do not want to change the flag if firstName does not match, then:

users.map((user) => userNames.includes(user.firstName) ? ({...user, flag: false}) : user)

edited Jul 27, 2022 at 15:45

answered Jul 27, 2022 at 15:09

Oki

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12 Comments

Ganesh Over a year ago

Lets check this

paddotk Over a year ago

userNames.includes() will look for whole matching items, in this case they are objects. It won't work.

Oki Over a year ago

userNames are not objects?! They are strings

Paperclip Over a year ago

String array as far as I can parse the OP

Oki Over a year ago

You are not doing something right or your question is not clear. This should work if you have 2 arrays, one of them is array of objects and the second one is array of strings, index of elements does not matter. If an element from array 2 matches firstName of an object from array 1, it should change it to false, else to true. It returns a new array, not changing the first one

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