How to change hexadecimal data format in python?

Question

i am beginner in python sorry... i have a series of data like this

b'B\x86\xfe\xca\x00\x00\x00\x00\x04\x08\x00\x00\xff\xff\xff\xff'

which i convert to hex

['0x42', '0x86', '0xfe', '0xca', '0x0', '0x0', '0x0', '0x0', '0x4', '0x8', '0x0', '0x0', '0xff', '0xff', '0xff', '0xff']

but i want to turn it into something like this

0x4286feca, 0x00004800, 0xffffffff

how can i do this? thanks so much

My code below >

brA = [b for b in struct.unpack(str(len(data))+'B',temp)]
sent_val = [str(hex(v)) for v in brA]

Does this answer your question? Python: binary/hex string conversion? — J. Choi
– J. Choi, Commented Jul 15, 2022 at 9:16
Note that CPython can't output bytes or int as hex like you want. You can, of course, create a str that looks like hex. — GordonAitchJay
– GordonAitchJay, Commented Jul 15, 2022 at 10:26

GordonAitchJay · Accepted Answer · 2022-07-15 10:22:08Z

0

data = b'B\x86\xfe\xca\x00\x00\x00\x00\x04\x08\x00\x00\xff\xff\xff\xff'

dwords_as_str = ["0x" + data[i:i+4].hex() for i in range(0, len(data), 4)]
print(dwords_as_str)

Output:

['0x4286feca', '0x00000000', '0x04080000', '0xffffffff']

See:

answered Jul 15, 2022 at 10:22

GordonAitchJay

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