Transform Array[Seq[(Int, String)]] to Seq[(Int, String)] in SCALA

Question

I'm pretty new to scala and I can't find a way to get rid of my Array[Seq[(Int, String)]] to one big Seq[(Int, String)] containing the (Int, String) of each Seq[(Int, String)].

Here is a more explicit example:

Array[Seq[(Int, String)]]:

ArrayBuffer((1,a), (1,group), (1,of))

ArrayBuffer((2,following), (2,clues))

ArrayBuffer((3,three), (3,girls))

And here is what I want my Seq[(Int, String)]] to looks like:

Seq((1,a), (1,group), (1,of), (2,following), (2,clues), (3,three), (3,girls))

Dima · Accepted Answer · 2022-06-02 12:12:05Z

2

You are looking for flatten: val flat: Array[(Int, String)] = originalArray.flatten

If you want it to be a Seq rather than an array (good choice), just tuck a .toSeq at the end: originalArray.flatten.toSeq

answered Jun 2, 2022 at 12:12

Dima

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Transform Array[Seq[(Int, String)]] to Seq[(Int, String)] in SCALA

Array[Seq[(Int, String)]]:

And here is what I want my Seq[(Int, String)]] to looks like:

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Array[Seq[(Int, String)]]:

And here is what I want my Seq[(Int, String)]] to looks like:

1 Answer 1

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