grep particular string from directory in Unix

Question

I have list of compressed files in a directory /var/log/bb e.g. console.log.1.xz, console.log.2.xz etc. I would like to grep a particular string from these files in a single command. Any ideas on how to achieve this

I have been trying like this

sudo xzcat /var/log/bb | grep 'string'

In grep 'string' you aren't greping a string, you're grepping a regexp so naming it string is misleading at best. You should either write grep 'regexp' or grep -F 'string', whichever it is you want to do. — Ed Morton
– Ed Morton, Commented Jun 1, 2022 at 15:40

sseLtaH · Accepted Answer · 2022-05-31 08:24:29Z

1

Using find

find /var/log/bb -iname '*.xz' -type f -exec grep 'string' {} +

Using grep

$ grep 'string' /var/log/bb/*.xz

answered May 31, 2022 at 8:24

sseLtaH

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Dudi Boy · Accepted Answer · 2022-05-31 19:19:51Z

0

Suggesting:

grep -l 'string' $(find /var/log/bb -type f -name "*.xz")

answered May 31, 2022 at 19:19

Dudi Boy

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