subtract same variables in single object javascript

Question

const token = [
  {"token":"d2r4Z62OTGiPyNmdHTUfny",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811},
  {"token":"eDZxQu0FSWm72D2-T1md5X",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811}]; // Try edit me
  const arr = [];
  for (var i=0; i<=token.length-1; i++)
  {
    const millis = Date.now();
    const time  = Math.floor(millis / 1000);
    if (token[i].time > time) {
      arr.push(token[i].token)
    }
   }
   console.log(arr);

between these two token variables are the same, I want to distinguish them from each other, how can I do that? Example Output:

const example = [
  "d2r4Z62OTGiPyNmdHTUfny",
  "eDZxQu0FSWm72D2-T1md5X",
  "dnl13twkQIqifdvaxp1t6e"
];
console.log(example);

you mean extracting unique token keys ? what's the purpose of 'time' ? try array.reduce — emre-ozgun
– emre-ozgun, Commented May 17, 2022 at 5:41

Robby Cornelissen · Accepted Answer · 2022-05-17 05:46:42Z

1

Just use a Set as it doesn't allow for duplicates:

const tokens = [
  {"token":"d2r4Z62OTGiPyNmdHTUfny", "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e", "time":1652767811},
  {"token":"eDZxQu0FSWm72D2-T1md5X", "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e", "time":1652767811}
];

const now = Math.floor(Date.now() / 1000);
const result = new Set(
  tokens.filter(({ time }) => time > now).map(({ token }) => token)
);

console.log(...result);

answered May 17, 2022 at 5:46

Robby Cornelissen

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Comments

Nick Vu · Accepted Answer · 2022-05-17 05:48:03Z

1

The easiest way with your current logic is that you can use includes to check token with the arr results. If it's in arr, we don't need to push it to arr.

const token = [
  {"token":"d2r4Z62OTGiPyNmdHTUfny",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811},
  {"token":"eDZxQu0FSWm72D2-T1md5X",
  "time":1652767811},
  {"token":"dnl13twkQIqifdvaxp1t6e",
  "time":1652767811}];
  const arr = [];
  for (var i=0; i<=token.length-1; i++)
  {
    const millis = Date.now();
    const time  = Math.floor(millis / 1000);
    if (!arr.includes(token[i].token) && token[i].time > time) {
      arr.push(token[i].token)
    }
   }
   console.log(arr);

edited May 17, 2022 at 5:48

answered May 17, 2022 at 5:42

Nick Vu

15.6k5 gold badges29 silver badges37 bronze badges

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