Adding vertically stacked 3 row subplots to matplotlib in for loop

Question

I have a for loop that is generating from a zipped list time series line plots.

Right now I have it so it is generates a single plot in a window. When the user clicks to close, the next plot shows.

I want to make it so that it displays all these plots with their own respective axis and values in rows of three vertically stacked.

I attemped this with the below code with just single vertical stacking by trying to loop through '''ax''' but it is generating the same plot. It is iterating over the same data but I am not sure how to logically change it so it iterates over each plot.

for title,unit, y, x, in zip(NameData,UnitData,value_list,dates_list):
        if np.size(y) > 0:
            fig, ax = plt.subplots(10)
            fig.supxlabel('Time')
            try:
                fig.supylabel('Units:' + unit)
            except TypeError:
                pass
            for i in range(1):
                ax[i].plot(x,y)
                ax[i].set_title(title)
            plt.show()     
            plt.close()
        else:
            pass

NameData: [Dog,Cat,Mouse]
UnitData: [mm, cm, nm]
value_list: [[1,2,3],[4,5,6],[7,8,9]]
dates_list: datetime[[1/27/2012,1/28/2012,1/29/2012],[1/27/2012,1/28/2012,1/29/2012],[1/27/2012,1/28/2012,1/29/2012]]

Davide_sd · Accepted Answer · 2022-04-12 21:08:07Z

3

Is this what you are trying to achieve?

fig, ax = plt.subplots(nrows=3, ncols=1, sharex=True)
fig.supxlabel('Time')
for i, (title, unit, y, x) in enumerate(zip(NameData,UnitData,value_list,dates_list)):
    ax[i].plot(x,y)
    ax[i].set_title(title)
    ax[i].set_ylabel(unit)
plt.tight_layout()

answered Apr 12, 2022 at 21:08

Davide_sd

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1 Comment

HotWheels Over a year ago

yes and +1 for optimizing - I adapted this to add more columns as well as keep the respective x axis

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