Split a String by a Regex in JavaScript

Question

I have the string:

"Vl.55.16b25.3d.42b50.59b30.90.24b35.3d.56.67b70.Tv.54b30.Vl.41b35.Tv.Bd.71b50.3d.99b20.03b50.Tv.73b50.Vl.05b25.12b40.Bd.Tv.82b25."

How to detached get results like:

["Vl.55.16b25", 3d.42.b50.59b30.90.24b35, 3d.56.67b70, ...]

The logic:

Condition 1: The End will be start b and 2 number. Example: b20, b25. If pass condition 1 I need to check condition 2.

Condition 2: maybe like "3d" or 2 characters. If don't match condition 2 we need to pass the next character to the current block.

Many thanks.

I did my best to improve the readability but this question is very unclear. You should be more clear about what kind of conditions you expect the logic to implement to return such a parsing from the input string — Diego D
– Diego D, Commented Apr 9, 2022 at 9:00

tybocopperkettle · Accepted Answer · 2022-04-09 19:54:37Z

1

If I understand your question correctly, the following code should work:

var string = "Vl.55.16b25.3d.42b50.59b30.90.24b35.3d.56.67b70.Tv.54b30.Vl.41b35.Tv.Bd.71b50.3d.99b20.03b50.Tv.73b50.Vl.05b25.12b40.Bd.Tv.82b25.";
console.log(string.split(/(?<=b\d\d)\.(?=3d)/g))

Explanation:

(?<=) is look-behind.
b matches the literal character "b".
\d matches any digit so \d\d will match two digits in a row.
\. matches a literal ".", it needs the \ before it because otherwise it would match any character.
(?=) is look-ahead.
The g flag stands for global so the string will be split up at every occurrence of the regular expression.

This means that the string will be split at every occurrence of "." that is preceded the letter "b" then two digits, and followed by "3d".

edited Apr 9, 2022 at 19:54

answered Apr 9, 2022 at 9:18

tybocopperkettle

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1 Comment

Khoi Hoang Over a year ago

That worked for me, but I think missing (Condition 2 maybe like "3d" or 2 characters) :). Thanks for your help.

Nina Scholz · Accepted Answer · 2022-04-09 09:03:20Z

0

Assuming you want to separate by last having 'b' and two digits followed by 3d, two digits or the end of string (this is necessary) and by omitting leading dot, you could take the following regular expression.

const
    string = "Vl.55.16b25.3d.42b50.59b30.90.24b35.3d.56.67b70.Tv.54b30.Vl.41b35.Tv.Bd.71b50.3d.99b20.03b50.Tv.73b50.Vl.05b25.12b40.Bd.Tv.82b25.",
    result = string.match(/[^.].*?b\d\d(?=\.(3d|\D\D|$))/g);

console.log(result);

answered Apr 9, 2022 at 9:03

Nina Scholz

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