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I am getting error push() is not a function while pushing element in >array? giving me error lik arry.push is not a function

 var abc=["get","get","get","get","get","get","get","get","get",];
    
     for(i=0;i<abc.length;i++){

    let a=abc[i].push("mate");
 
   console.log(abc);
    }
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  • read more about how .push works. Commented Mar 22, 2022 at 6:42
  • abc is an array, abc[i] is an element of the array, in your case a string. strings don't have a push method ... Commented Mar 22, 2022 at 6:43
  • Can you give me any alternative to replace all element of array with new one using for loop? Commented Mar 22, 2022 at 11:31

4 Answers 4

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You should delete the [i] in abc[i].push() because abc[i] is string, but the .push() method works for arrays. Therefore you should use abc.push() instead of abc[i].push().

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Comments

1

When you do abc[i].push(), you're actually calling .push() on the string at index i, not the array. Strings do not have the function .push() which is where your error is coming from

Instead try the following:

abc.push("mate");

Comments

0

To push elements in an array, simply use the Array.prototype.push method.

var abc = ["get", "get", "get", "get", "get", "get", "get", "get", "get"]

abc.push("mate")

Read more about how push works here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/push

The origin point of your error is that, you are accessing each array elements which are strings and trying to use the push() method on those.

Comments

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The .push() method is for array only. In the loop, you're using abc[i] which means you're accessing each element of the array, not the whole array..

The above method works to add element to end of the array. So use abc.push()

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