How to convert a string representation of bytearray to a numpy array?

Question

I have a string like this:

string = "b'\\xf4\\xf0\\xf2\\xef\\xf8\\xf2\\xee'"

So far I have come up with this:

arr = np.array([int(s_num, 16) for s_num in re.findall(r'x([a-f0-9]{2})', string)], dtype=np.uint8)

For large strings this gets really slow. What is the best way to convert the string to a numpy array (of data type np.uint8)? Thanks.

You really shouldn't have that string to begin with, but rather b'\\xf4\\xf0\\xf2\\xef\\xf8\\xf2\\xee'. How did you get that? — Kelly Bundy
– Kelly Bundy, Commented Mar 1, 2022 at 14:55

mozway · Accepted Answer · 2022-03-01 14:54:43Z

2

What about:

from ast import literal_eval

np.frombuffer(literal_eval(string), dtype=np.uint8)

output: array([244, 240, 242, 239, 248, 242, 238], dtype=uint8)

answered Mar 1, 2022 at 14:54

mozway

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