Regex part of URL string

Question

I have the following strings

https://test.com/fi/wp-content
https://test.com/fr
https://test.com/es
https://test.com/
https://test.com/wp-content/
https://test.com/image.png
https://test.com/de/wp-content/themes
https://test.com/es
https://test.com/fr
https://test.com/no
https://test.com/da
https://test.com/en
https://test.com/de
https://test.com/nl/wp-content
https://test.com/fi

As far as now I have the following regex

/\btest.com.*\.*(?<!fr|es|da|no|en|de|nl|fi)$/gm

I want to match the following (image 1)

Im almost there but my regex matches everything after my expression like this (image 2):

I can seem to figure out how to get the end of my regex to behave so it produces the match as image 1. Here is a regex101: https://regex101.com/r/Tv0AjJ/1

It should be like this \btest\.com\/(?!fr|es|d[ae]|no|en|nl|fi) regex101.com/r/P5dgv8/1 — The fourth bird
– The fourth bird, Commented Feb 23, 2022 at 15:05
It should actually be \btest\.com\/(?!(?:fr|es|da|no|en|de|nl|fi)\/) or even \btest\.com\/(?!(?:fr|es|da|no|en|de|nl|fi)(?:\/|$)) — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Feb 23, 2022 at 15:09

The fourth bird · Accepted Answer · 2022-02-23 15:18:25Z

2

Currently this part .*(?<!fr|es|da|no|en|de|nl|fi)$ matches until the end of the string and asserts what is to the left is not any of the alternatives, that is why /es does not match but .png does.

You can match the / and then assert not any of the alternatives directly to the right using a negative lookahead (?!

Note to escape the the dot.

\btest\.com\/(?!fr|es|d[ae]|no|en|nl|fi)

Regex demo

If you don't want partial matches, you can either group the alternatives themselves again follwed by a word boundary \b or as Wiktor Stribiżew mentioned in the comments a forward slash or the end of the string (?:\/|$)

Alternatives that have the same character can be grouped together in a character class d[ae]

\btest\.com\/(?!(?:fr|es|d[ae]|no|en|nl|fi)\b)

answered Feb 23, 2022 at 15:18

The fourth bird

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