How to insert array to array PHP

Question

I have arrays, I don't know how to fix I already try array_push, array_combine, array_merge, but still nothing.

$distance = array(3) {
  [0]=>
  float(2.2)
  [1]=>
  float(1.1)
  [2]=>
  float(3.9)
}
$getID = array(3) {
  [0]=>
  string(1) "B"
  [1]=>
  string(1) "C"
  [2]=>
  string(1) "F"
}

I want to

array(3) {
  [0]=> ["B", 2.2]
  [1]=> ["C", 1.1]
  [2]=> ["F", 3.9]
}

this is my code

function mergeArray($distance, $getID)
{
    $mergeArray = array();
    for ($i = 0; $i < count($distance); $i++) {
        $mergeArray[] = array_splice($getID, $distance[$i]);
    }
    return $mergeArray;
}

Edited help me please thx

Please show us your attempts and the their results. We're glad to help you sort out specific issues you run into with your implementation, but we're not here to write it all for you (which a proper answer here would require us to) — M. Eriksson
– M. Eriksson, Commented Jan 23, 2022 at 11:56

M. Eriksson · Accepted Answer · 2022-01-23 12:11:16Z

2

You don't need "array_combine()", "array_slice()" or similar. Just iterate through the data and create a new one:

$a = [2.2, 1.1, 3.9];
$b = ["B", "C", "F"];

$new = [];
foreach ($a as $index => $value) {
    $new[] = [
        $b[$index], // Fetch the value with the same index from the other array
        $value
    ];
}

Demo: https://3v4l.org/oseSV

answered Jan 23, 2022 at 12:11

M. Eriksson

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Comments

Elias Soares · Accepted Answer · 2022-01-23 12:23:14Z

You can use array_map to iterate over two arrays simultaneously and produce a new array:

$distance = array(3) {
  [0]=>
  float(2.2)
  [1]=>
  float(1.1)
  [2]=>
  float(3.9)
}
$getID = array(3) {
  [0]=>
  string(1) "B"
  [1]=>
  string(1) "C"
  [2]=>
  string(1) "F"
}

$output = array_map(function ($d, $id) {
    return [$id, $d];
}, $distance, $getID);

Note that this code assumes that both arrays have the same length.

Offtopic:

A little advice about your code: always name your variable with something that allows you to know what's inside it, using correct plural too:

Your $distance variable contains an array off distances, so it nsme should be in plural.

Your $getID is not a function, so it should not be called get, but just $Ids instead.

lukas.j · Accepted Answer · 2022-01-23 12:13:43Z

0

$distance = [ 2.2, 1.1, 3.9 ];
$getID = [ "B", "C", "F" ];

$result = array_map(fn(string $id, float $distance) => [ $id, $distance ], $getID, $distance);

print_r($result);

answered Jan 23, 2022 at 12:13

lukas.j

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Comments

Rabyâ Raghib · Accepted Answer · 2022-01-23 12:39:56Z

0

For your current code to work you have to:

pass both elements to array_splice function as an array
pass the offset of where the function need to replace the value
as well as the number of how many elements should be removed
You should not reassign $mergeArray because array_splice work with pointer

Checkout the docs for more!

function mergeArray($distance, $getID)
{
    $mergeArray = [];
    for ($i = 0; $i < count($distance); $i++) {
        array_splice($mergeArray,$i,1, [[
             $distance[$i],
             $getID[$i]
        ]]);
    }
    return $mergeArray;
}

however a better approach is to do as in M. Eriksson's ansewar.

answered Jan 23, 2022 at 12:39

Rabyâ Raghib

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