Pass multiple arguments (each argument is a list) from bash script to python script

I am having a python file that take multiple arguments, each argument is a list. For example, it takes a list of year and a list of month.The test.py is below:

import sys

def Convert(string):
    li = list(string.split(" "))
    return li


year= Convert(sys.argv[1])
month = Convert(sys.argv[2])

print("There are",len(year),"year(s)")
print("There are",len(month),"month(s)")


for i in range(len(year)):
    print("Working on year",year[i])
    for j in range(len(month)):
        print("Working on month",month[j])

Just FYI, I used Convert() to convert arguments into lists. For example, with an argument of "2021 2020",year[1] will return 2(instead of 2021) and year[2] will return 0 (instead of 2020) without being converting into a list first. Not sure this is the most accurate way to do it though.If you know a better way, please comment down below.

Anyway, my main struggle is that in command line, if I run

python test.py "2021 2020" "9 10"

It worked fine.And below is the printed message:

There are 2 year(s). There are 2 month(s). Working on year 2021. Working on month 9. Working on month 10. Working on year 2022. Working on month 9. Working on month 10.

However, now I have a test.sh script that can take the same arguments then pass into python, the bash script just simply won't work.The test.shscript is below:

#!/bin/bash

# year month as arguments.
year=$1
month=$2

echo 'Working on year' $year 
echo 'Working on month' $month

python path/test.py $year $month

Then in command line, I ran this

sh test.sh "2021 2022" "9 10"

Python seems to believe "2021 2022" "9 10" is 4 arguments instead of 2 even though I quote them separately. Here is the message it prints:

There are 1 year(s). There are 1 month(s). Working on year 2021. Working on month 2022.

How do I fix this?