For example, I have 2 arrays:
arr1 = ["a","e","i","o","u"];
arr2 = ["h", "e", "l", "l", "o"];
I would like to find whether any of the elements in arr2 contain any of the elements that are already available in arr1.
3 Answers
Use Array.some to check whether one of the items in arr2 is included in arr1:
arr1 = ["a", "e", "i", "o", "u"];
arr2 = ["h", "e", "l", "l", "o"];
const res = arr2.some(e => arr1.includes(e))
console.log(res)
Comments
Find the array with below filter function
let array1 = ["a","e","i","o","u"];
let array2 = ["h", "e", "l", "l", "o"];
const filteredArray = array1.filter(value => array2.includes(value));
filteredArray.length will give you the answer
2 Comments
Nishant
you can use
.some instead of filter.
DexieTheSheep
The guy said they wanted to know "whether" any of them are in the other array. It depends on your use case, but yeah it seems like they don't care about the actual values inside the arrays.
Try this.
arr1 = ["a","e","i","o","u"];
arr2 = ["h", "e", "l", "l", "o"];
let res = arr1.some(el1 => {
return arr2.some(el2 => el1 === el2);
});
console.log(res) // true
arr1 = ["a","e","i","o","u"];Please edit your question to fix the code.