I have written a function f(x) that either returns a dictionary or an error message.
def myfunc():
try:
return dictionary
except BaseException as e:
return e
return_value = myfunc()
if return_value a dictionary:
do this
else:
do that
I need to detect the type of return in another function f(y) which calls f(x).
How do I do that?
thanks in advance
Your example does not follow normal best practices, but you would do the following:
if type(return_value) is dict:
or
if isinstance(return_value, dict):
isinstance(return_value, dict)
You can check a value's type as follows:
if type(return_value) == dict:
print("It is a dictionary.")
else:
pinrt("It is not a dictionary")
There are several ways to check a type of value, see: How to check if type of a variable is string?
An alternative is to return a tuple that keeps track of whether there was an error:
def myfunc():
try:
return (True, dictionary)
except BaseException as e:
return (False, e)
was_successful, return_value = myfunc()
if was_successful:
do this
else:
do that
try ... catchoutsidemyfunc(), since on error the function will pass the exception to the caller.myfunc().returnan exception instance. You should just let it be raised. That's the point of how exceptions work.