Object.Create calling function with prototype

Question

Oke, I have this working:

const personProto2 = {
  calAge() {
    console.log(2021 - this.birthday);
  },
};

const rein = Object.create(personProto2);
rein.name = "Rein";
rein.birthday = 1945;
rein.calAge();

But if I do this:

const Person = function (name, birthday) {
  this.name = name;
  this.birthday = birthday;
};

Person.prototype.calAge = function () {
  console.log(2021 - this.birthday);
};

const rein = Object.create(Person);
rein.name = "Rein";
rein.birthday = 1945;
rein.prototype.calAge();

It doesn't work. But a function is also a object. And a object has also a prototype.

So why the second example doesn't work?

Ran Turner · Accepted Answer · 2021-10-26 11:59:06Z

1

I think that you meant using new when creating a blank, plain JavaScript object.

The new operator lets you create an instance of a user-defined object type or of one of the built-in object types that has a constructor function. now, you can call the calAge method.

function Person(name, birthday) {
  this.name = name;
  this.birthday = birthday;
};

Person.prototype.calAge = function () {
  console.log(2021 - this.birthday);
};

const rein = new Person("Rein", 1945);
rein.calAge();

answered Oct 26, 2021 at 11:59

Ran Turner

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1 Comment

mightycode Newton Over a year ago

Thank you. Ah, oke. So a function is an object. But function name(){} doens't create a object with Object.create. And {} with Object.create createds an object.

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