I want to make i into 3 in file s2.py, but it keeps becoming 1.
File s1.py
i=1
class a():
def f():
global i
i = 3
File s2.py
from s1 import *
a.f()
print(i)
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Does this answer your question? How to modify variables in another python file?Tomerikoo– Tomerikoo2021-10-16 21:31:26 +00:00Commented Oct 16, 2021 at 21:31
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5 Answers
Every module has its own global scope, and Python is lexically scoped, meaning a.f refers to the global scope of s1 no matter where it is called from. i is initialized to the value of s1.i, but is otherwise independent of it. Changes to s1.i do not affect s2.i.
Comments
You have to re-import your variable after calling your method if you want to see any changes made.
#s1.py
i=1
class a():
def f():
global i
i = 3
#s2.py
from s1 import *
a.f()
from s1 import i
print(i)
Comments
#s1.py
i=1
class a():
def f():
global i
i += 3
#s2.py
import s1
s1.a.f()
print(s1.i)
1 Comment
Jeremy Caney
Welcome to Stack Overflow, and thank you for contributing an answer. Would you kindly edit your answer to to include an explanation of your code? That will help future readers better understand what is going on, and especially those members of the community who are new to the language and struggling to understand the concepts.
I believe you are referencing the local variable i and aren't referencing the instance of i in the class. Try this.
print(a.i)
1 Comment
Donald Duck is with Ukraine
There isn't any instance of
i in the class. Calling print(a.i) will throw an error. There are only two instances if i, one in s1 and one in s2 (created using from s1 import *).Reimport the variable after calling the method:
File s1.py
i = 1
class a():
def f():
global i
i += 3
File s2.py
import s1
s1.a.f()
print(s1.i)
Comments
