Filter and MAP Object inside Object in Javascript

Question

How I can use the filter to populate the variable onlyAmountLess5? I want to filter only products where sales' amount < 5:

const products = [
    { id: 1, name: "bread", value: 2.0, category: "bakery", "sales":[{"day": "07/04/2021", "amount": 12}, {"day": "10/04/2021", "amount": 18}] },
    { id: 2, name: "apple", value: 6.5, category: "fruit", "sales":[{"day": "07/04/2021", "amount": 4}, {"day": "10/04/2021", "amount": 18}] },
    { id: 3, name: "pizza", value: 2.0, category: "food", "sales":[{"day": "07/04/2021", "amount": 5}, {"day": "10/04/2021", "amount": 18}]} ,
    { id: 4, name: "cheese", value: 7.0, category: "bakery", "sales":[{"day": "07/04/2021", "amount": 12}, {"day": "10/04/2021", "amount": 5}] },
    { id: 5, name: "milk", value: 2.2, category: "food", "sales":[{"day": "07/04/2021", "amount": 12}, {"dia": "10/04/2021", "amount": 3}]}
  ];

const onlyBakery = products.filter( p => p.category ==="bakery")
console.log(onlyBakery);

// List only product where sales amount < 5
const onlyAmountLess5 = products.filter(o => products.sales.amount < 4)

But sales is an array right. If even one of the sales from product is less than 5 you want to show it or only if all of them? — Tushar Shahi
– Tushar Shahi, Commented Oct 12, 2021 at 19:21

Erik · Accepted Answer · 2021-10-13 04:51:11Z

1

The field sales has two amounts. If you want to check them all you can do it like this:

const maxAmount = 5;
const onlyAmountLess5 = products.filter(product => product.sales.some(item => item.amount < maxAmount));

edited Oct 13, 2021 at 4:51

answered Oct 12, 2021 at 19:25

Erik

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1 Comment

TulioVargas Over a year ago

Thank you Erik. in case of both amounts must be less than 5, how I could do it?

The fourth bird · Accepted Answer · 2021-10-12 20:06:00Z

0

If you want to select the entry where all the amounts are less than 5, you can use every

Note that it would give an empty array, as for none of the example all objects have an amount lesser than 5.

Mind that < 4 is not the same as <5. You could also write <=4 instead.

const products = [
    { id: 1, name: "bread", value: 2.0, category: "bakery", "sales":[{"day": "07/04/2021", "amount": 12}, {"day": "10/04/2021", "amount": 18}] },
    { id: 2, name: "apple", value: 6.5, category: "fruit", "sales":[{"day": "07/04/2021", "amount": 4}, {"day": "10/04/2021", "amount": 18}] },
    { id: 3, name: "pizza", value: 2.0, category: "food", "sales":[{"day": "07/04/2021", "amount": 5}, {"day": "10/04/2021", "amount": 18}]} ,
    { id: 4, name: "cheese", value: 7.0, category: "bakery", "sales":[{"day": "07/04/2021", "amount": 12}, {"day": "10/04/2021", "amount": 5}] },
    { id: 5, name: "milk", value: 2.2, category: "food", "sales":[{"day": "07/04/2021", "amount": 12}, {"dia": "10/04/2021", "amount": 3}]}
];
const onlyAmountLess5 = products.filter(o =>o.sales.every(i => i.amount < 5));
console.log(onlyAmountLess5);

An example using < 13 to return 2 entries:

const products = [
    { id: 1, name: "bread", value: 2.0, category: "bakery", "sales":[{"day": "07/04/2021", "amount": 12}, {"day": "10/04/2021", "amount": 18}] },
    { id: 2, name: "apple", value: 6.5, category: "fruit", "sales":[{"day": "07/04/2021", "amount": 4}, {"day": "10/04/2021", "amount": 18}] },
    { id: 3, name: "pizza", value: 2.0, category: "food", "sales":[{"day": "07/04/2021", "amount": 5}, {"day": "10/04/2021", "amount": 18}]} ,
    { id: 4, name: "cheese", value: 7.0, category: "bakery", "sales":[{"day": "07/04/2021", "amount": 12}, {"day": "10/04/2021", "amount": 5}] },
    { id: 5, name: "milk", value: 2.2, category: "food", "sales":[{"day": "07/04/2021", "amount": 12}, {"dia": "10/04/2021", "amount": 3}]}
];
const onlyAmountLess5 = products.filter(o =>o.sales.every(i => i.amount < 13));
console.log(onlyAmountLess5);

answered Oct 12, 2021 at 20:06

The fourth bird

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2 Comments

TulioVargas Over a year ago

Hi The fourth bird, can you fix this filter? I just add one more element "customers" `

The fourth bird Over a year ago

@TulioVargas You unselected the mark as answer, but the provided answer is for the related question.

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