Python if statement errors while using inport random

Question

I’m trying to use an if statement to determine if a certain text is in the input and that used to work fine until I used input random and now my if statement is returning a syntax error.

command_1=input()

post_type_fg="/post-fg"
post_type_ot="/post-ot"
post_type_sb="/post-sb"
post_type_gh="/post-gh"
post_type_hym="/post-hym"

import random
post_post_count= random.randint(1,10)
temp_post_like_count= random.randint(0,((post_post_count * 2))




if  post_type_fg in command_1:
        print("You posted",command_1[8:],"in the section forum games")
        print("Post Count:", post_post_count)
        print("Like Count: (", post_like_count, "*")

else: 
    
    print("error command 1")

Daweo · Accepted Answer · 2021-10-12 11:45:53Z

1

Problem is caused by previous line, i.e.:

temp_post_like_count= random.randint(0,((post_post_count * 2))

you have unbalanced brackets (more ( than )). If you got SyntaxError but pointed line does not show any error then there is good chance, that problem is actually in previous line.

answered Oct 12, 2021 at 11:45

Daweo

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