Trying to add each table item to an array using JQuery

Question

Basically what the title says... just having trouble getting it to work and couldn't find a solution online.

Code:

    var arr=new Array();
    $('#tableC tr').each(function() {
        var tr = $(this);
        tr.find('td').each(arr, function() {
            $(this).val();
        });
    });

Indeed. @Slaks♦ is correct. Use .text() instead.

Joseph Marikle
– Joseph Marikle

2011-08-03 18:43:15 +00:00
Commented Aug 3, 2011 at 18:43 — Joseph Marikle
– Joseph Marikle, Commented Aug 3, 2011 at 18:43

ShankarSangoli · Accepted Answer · 2011-08-03 18:40:08Z

2

Try this

var arr = [];
    $('#tableC td').each(function() {
        arr.push($(this).text());
    });

answered Aug 3, 2011 at 18:40

ShankarSangoli

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Comments

SLaks · Accepted Answer · 2011-08-03 18:51:24Z

2

You're completely miscalling each.

Instead, write

tr.find('td').each(function() {
    arr.push($(this).val());
});

You could also write

var arr = $("#tableC tr td").map(function() { return $(this).val(); }).get();

edited Aug 3, 2011 at 18:51

answered Aug 3, 2011 at 18:39

SLaks

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1 Comment

user113716 Over a year ago

arr.append ? What are you using Chrome v18 with support for ECMAScript 7th edition? ;o)

Community · Accepted Answer · 2020-06-20 09:12:55Z

0

Something along these lines?

http://jsfiddle.net/pPxcE/

Edit

code

var arr=new Array();
$('#tableC tr').each(function() {
    var tr = $(this);
    tr.find('td').each(function() {
        arr.push($(this).text());
    });
});

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Aug 3, 2011 at 18:42

Joseph Marikle

78.8k18 gold badges114 silver badges130 bronze badges

5 Comments

user113716 Over a year ago

I didn't down vote you, but it may be because you posted a link to another site in lieu of the actual code for your solution.

SLaks Over a year ago

Please put more than just a link in your answer. In particular, you should include the code here.

Joseph Marikle Over a year ago

everyone does... that's what fiddles are for. I've never gotten a downvote for using jsfiddle... posters are even told to use the site to help us answer their questions.

user113716 Over a year ago

@Joseph: StackOverflow is intended to be an independent repository of questions and answers. Sometimes jsFiddle is down (or extremely slow), making your answer useless at those times to future readers. I'll +1 for your solution, and for the update. :o)

Joseph Marikle Over a year ago

@patrickdw Thank you, patrick. I'll use it as strictly supplementary from now on.

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