javascript variables problem

Question

$.getJSON("/data/data/com.android.tcptest/files/BPL.json", function(data) {
        var i = 0, dataSize = data.length, tmpArray = [];
        for(i; i < dataSize; i++){
            tmpArray.push ([data[i].Time.substring(0, data[i].Time.length -2).replace(/:/g, ""),data[i].Bid ]);
        }
        return tmpArray;
    });
    $.plot($("#chart"), [ tmpArray ]);

How can I use tmpArray outside getJSON() function. My programme doesn't work. Thanks!

This question is similar to: How do I return the response from an asynchronous call?. If you believe it’s different, please edit the question, make it clear how it’s different and/or how the answers on that question are not helpful for your problem. — dumbass
– dumbass, Commented Oct 8, 2024 at 22:11

imsky · Accepted Answer · 2011-08-02 15:41:51Z

1

Initialize tmpArray outside of the getJSON block.

Edit: Quentin is right, the array would be empty. You'll also need to make the request synchronous. I wrote the following example, hope it helps: http://jsfiddle.net/mXHfC/

edited Aug 2, 2011 at 15:41

answered Aug 2, 2011 at 15:00

imsky

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3 Comments

SPG Over a year ago

Could you should me how to do that?

Quentin Over a year ago

Then you'll just be passing an empty array to plot.

SPG Over a year ago

Could u tell me how to do that? I tried "tmpArray =[]" outside getJSON but still fail.

Quentin · Accepted Answer · 2011-08-02 15:02:55Z

0

Asynchronous JavaScript and XML is asynchronous.

You can't return from it, any more then you could return from:

$('button').click(function () {
    return tmpArray;
});
$.plot($("#chart"), [ tmpArray ]);  /* Does this method really expect an array consisting of a single value that is another array? */

The code in the callback won't execute until after the HTTP response has arrived (or the button has been clicked).

Do the work inside the callback.

$.getJSON("/data/data/com.android.tcptest/files/BPL.json", function(data) {
    var i = 0, dataSize = data.length, tmpArray = [];
    for(i; i < dataSize; i++){
        tmpArray.push ([data[i].Time.substring(0, data[i].Time.length -2).replace(/:/g, ""),data[i].Bid ]);
    }
    $.plot($("#chart"), [ tmpArray ]);  
});

answered Aug 2, 2011 at 15:02

Quentin

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1 Comment

SPG Over a year ago

I tried this before, this work in brower but android. Put plot outside function works on android but only with some stastic values. like [[1,2],[2,3],[4,5]]

epascarello · Accepted Answer · 2011-08-02 15:03:26Z

0

getJSON is asynchronous, you can not use the array before the function is returned!

$.getJSON("/data/data/com.android.tcptest/files/BPL.json", function(data) {
        var i = 0, dataSize = data.length, tmpArray = [];
        for(i; i < dataSize; i++){
            tmpArray.push ([data[i].Time.substring(0, data[i].Time.length -2).replace(/:/g, ""),data[i].Bid ]);
        }
        $.plot($("#chart"), [ tmpArray ]);  
        //return tmpArray;
    });

answered Aug 2, 2011 at 15:03

epascarello

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2 Comments

SPG Over a year ago

This is working fine with brower but when I put this into android--->failed. I tried to put plot outside getjson and give it some specific value(like[[1,2],[3,4],[5,6]]). It works. Confuse!!!

epascarello Over a year ago

Are you sure the android device is calling the success function? Is it creating an array correctly?

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