Bash 'for' loop syntax?

Question

What is the syntax for a Bash for loop?

I have tried:

for (($i=0;$i<10;$i ++))
do
    echo $i
done

I get this error:

line 1: ((: =0: syntax error: operand expected (error token is "=0")

First google search result for "bash for loop" is pretty good, but this page is much better. — Ray Toal
– Ray Toal, Commented Jul 28, 2011 at 4:37

jman · Accepted Answer · 2013-08-28 21:08:01Z

16

Replace

for (($i=0...

with

for ((i=0;i<10;i++))

edited Aug 28, 2013 at 21:08

answered Jul 28, 2011 at 4:33

jman

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1 Comment

jman Over a year ago

@Laurent, reverted as it doesn't fit in with the rest of the answer (replace x by y).

Peter Mortensen · Accepted Answer · 2016-02-13 18:52:23Z

11

The portable way is:

for i in `seq 0 9`
do
    echo "the i is $i"
done

edited Feb 13, 2016 at 18:52

Peter Mortensen

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answered Jul 28, 2011 at 21:50

Michał Šrajer

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2 Comments

laurent Over a year ago

That would loop from 1 to 10 instead of 0 to 9.

Michał Šrajer Over a year ago

@Laurent: Fixed that. Good catch.

Eric Fortis · Accepted Answer · 2011-07-28 04:37:10Z

7

Another way

for i in {0..9}
  do
    echo $i
  done

answered Jul 28, 2011 at 4:37

Eric Fortis

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