Python Selenium. Can't click on a button

Question

Hi I'm trying to click on this button "Next" on this link: https://www.sneakql.com/en-GB/launch/culturekings/womens-air-jordan-1-high-og-court-purple-au/register

I tried this but It didn't work...

chrome.find_element_by_xpath('//*[@id="gatsby-focus-wrapper"]/main/div[2]/div[2]/div[2]/div/div/div[2]/div/form/div[3]/div/div/div/button').click();

I'm getting this:

selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element <button class="MuiButtonBase-root MuiButton-root MuiButton-contained MuiButton-containedPrimary MuiButton-fullWidth" tabindex="0" type="submit">...</button> is not clickable at point (456, 870). Other element would receive the click: <div class="jss3" style="flex: 1 0 300px; margin: 15px;">...</div>

selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element <button class="MuiButtonBase-root MuiButton-root MuiButton-contained MuiButton-containedPrimary MuiButton-fullWidth" tabindex="0" type="submit">...</button> is not clickable at point (456, 870). Other element would receive the click: <div class="jss3" style="flex: 1 0 300px; margin: 15px;">...</div> — abc
– abc, Commented Jun 1, 2021 at 12:06

itronic1990 · Accepted Answer · 2021-06-01 12:11:08Z

2

"Agree" button and "Next button" has similar class name and so "Agree" button is receiving the click.

See if this works:-


driver.find_element_by_xpath(".//button[contains(@class,'MuiButton-containedPrimary') and @type='submit']").click()

edited Jun 1, 2021 at 12:11

answered Jun 1, 2021 at 12:08

itronic1990

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3 Comments

abc Over a year ago

Same problem as before : selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element <button class="MuiButtonBase-root MuiButton-root MuiButton-contained MuiButton-containedPrimary MuiButton-fullWidth" tabindex="0" type="submit">...</button> is not clickable at point (456, 870). Other element would receive the click: <div class="jss3" style="flex: 1 0 300px; margin: 15px;">...</div> (Session info: chrome=90.0.4430.212)

itronic1990 Over a year ago

You have to accept the cookies by this xpath ".//button[@id='rcc-confirm-button']" and then try the xpath for Next button

vitaliis Over a year ago

You were very close to the full answer. Click did not work because of cookies button.

Pedro Kaneto Suzuki · Accepted Answer · 2021-06-01 12:24:00Z

1

You can just click with JS

button = chrome.find_element_by_xpath('//*[@id="gatsby-focus-wrapper"]/main/div[2]/div[2]/div[2]/div/div/div[2]/div/form/div[3]/div/div/div/button')
chrome.execute_script("arguments[0].click();", button)

answered Jun 1, 2021 at 12:24

Pedro Kaneto Suzuki

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1 Comment

vitaliis Over a year ago

As soon as DOM structure changes, even this approach will stop working. It is recommended to not use full xpath in UI automation because it's unstable. But is is a good option when Selenium's click does not work even with short locators.

Prophet · Accepted Answer · 2021-06-01 12:32:14Z

1

Try this:

from selenium.webdriver.common.action_chains import ActionChains

next_btn = driver.find_element_by_xpath('//span[@class="MuiButton-label" and contains(text(),"Next")]')

actions = ActionChains(driver)
actions.move_to_element(next_btn).perform()

If this doesn't help - try adding a simple

time.sleep(5)

before clicking on that button

edited Jun 1, 2021 at 12:32

answered Jun 1, 2021 at 12:14

Prophet

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2 Comments

abc Over a year ago

it does not locate the button : selenium.common.exceptions.InvalidSelectorException: Message: invalid selector: Unable to locate an element with the xpath expression //span[@class="MuiButton-label" and contains(text()," because of the following error: SyntaxError: Failed to execute 'evaluate' on 'Document': The string '//span[@class="MuiButton-label" and contains(text(),"' is not a valid XPath expression.

Prophet Over a year ago

You are right, sorry. My mistake with copy-pasting the locator. I've corrected the answer

vitaliis · Accepted Answer · 2021-06-01 18:58:55Z

0

You can click it as I suggested in another your question, with xpath and waiting till it's clickable:

wait.until(EC.element_to_be_clickable((By.XPATH, "//span[contains(text(),'Next')]"))).click()

But before clicking this button, you will have to accept the cookies:

wait = WebDriverWait(driver, 15)
wait.until(EC.element_to_be_clickable((By.XPATH, "//span[contains(text(),'AGREE')]"))).click()

For this you will need to import:

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

answered Jun 1, 2021 at 18:58

vitaliis

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