(function(arguments = {})
{
console.log(arguments)
}
)("a","b","c")
prints
$ node args.js
a
$ node --version
v8.9.4
Is there a way to access the actual arguments in that case?
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2 Answers
I would advise against overriding the built-in arguments variable within a function definition.
You could spread the expected arguments instead using ...vargs.
(function(...vargs) {
console.log(arguments); // Built-in arguments
console.log(vargs); // Variable (spread) arguments
})("a", "b", "c");.as-console-wrapper { top: 0; max-height: 100% !important; }Please take a look at the arguments object over at MDN for more info.
The documentation notes that if you are using ES6 syntax, you will have to spread the arguments, because the arguments do not exist inside of an arrow (lambda or anonymous) function.
((...vargs) => {
try {
console.log(arguments); // Not accessible
} catch(e) {
console.log(e); // Expected to fail...
}
console.log(vargs); // Variable (spread) arguments
})("a", "b", "c");.as-console-wrapper { top: 0; max-height: 100% !important; }
Comments
function f1() { console.log(Array.from(arguments)) }
f1(1, 2, 3)
function f2(...args) { console.log(args) }
f2(4, 5, 6)
Comments
