Accessing the member in a struct array in a struct with a pointer

Question

the title pretty much says it all i have a struct with an array of struct as one of its member and I can't figure out how to access

struct Member{
   short x;
...
};

struct List{
   struct Member members[MAX_MEMBER];
...
};
short function(const struct List*n){
 if((n->members[i])->x ...)
...
}

I tried somethin like that but it doesn't work. Thanks for your answer

You need .x instead of ->x. n->members[i] is a struct Member, so you don't need the pointer arrow notation. And the parentheses are unnecessary too. If you're perverse enough, you could use (&n->members[i])->x, but that is silly. — Jonathan Leffler
– Jonathan Leffler, Commented May 11, 2021 at 15:05

Nate Eldredge · Accepted Answer · 2021-05-11 15:08:44Z

2

n->members is an array of struct Member, not an array of pointers. Hence n->members[i] is a struct Member, not a struct Member *. You should therefore access its members using . and not ->. Try:

if (n->members[i].x ...)

edited May 11, 2021 at 15:08

answered May 11, 2021 at 15:06

Nate Eldredge

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