a basic eight number string to eight bit binary number [duplicate]

Question

eight character (zero and one) string -> turn it into 8 bit binary number -> perform binary operation -> turn back into 8 0/1 string

>>> the_entry = "00000000"
>>> the_binary number = 8CharacterStringIntoThe8CharacterBinaryNumber(the_entry)
>>> the_binary_number << 1 # any binary operation
>>> the_result_string = EightCharacterBinaryNumberIntoEightCharacterString(the_binary_number)

this is soo simple, I refuse to write my own method, but obviously, in th 180000 possible results, I cannot find the one related to my question.

Do you hold the magic??

I didn't understand what your question is. Can you please phrase this more clearly? — mkrieger1
– mkrieger1, Commented May 4, 2021 at 13:21
I would like to turn an eight number string into an 8 bit binary number, perform bitwise operations on the binary and return the 8character string representation of this number — frank
– frank, Commented May 4, 2021 at 13:23
Are you asking this? (1) stackoverflow.com/questions/8928240/…; (2) stackoverflow.com/questions/699866/python-int-to-binary-string — mkrieger1
– mkrieger1, Commented May 4, 2021 at 13:23
"I refuse to write my own method" That's not how to win a crowd... — MisterMiyagi
– MisterMiyagi, Commented May 4, 2021 at 13:23
I am reluctant of reinventing the wheel, maybe that would sound better] — frank
– frank, Commented May 4, 2021 at 13:28

Daniel · Accepted Answer · 2021-05-04 13:23:37Z

1

These are simple basic operations:

entry = "00000000"
number = int(entry, 2)
result = f"{number:08b}"

answered May 4, 2021 at 13:23

Daniel

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2 Comments

frank Over a year ago

but then your number will be an integer, not a binary or byte ...

frank Over a year ago

This was it!! thank you so much!! simple and concise

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