I want to be able to parse below strings with a single regex using groups? There may or may not be single/multiple whitespace between dash and numbers.
Input string examples:
"0.4 - 1.2 Mathematics" "0.7-1.3 Physics" "0.3- 0.7 Chemistry" "4.5 Biology" "2 Calculus" group(1) -> lowGrade -> Float group(2) -> highGrade -> Float (if exists) group(3) -> class -> String
Can you help with the regex? Thanks
So here is your working solution, if the "highGrade" is not available the second group is NULL.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main
{
public static void main(String[] args)
{
String Text = "0.4 - 1.2 Mathematics";
Pattern p = Pattern.compile("^" + // Match the start of the string
"(\\d+(?:\\.\\d+)?)" + // Match the first float, the fraction is optional, (?:) is a non capturing group
"(?:\\s*-\\s*" + // Match the whitespace and the - . This part including the following float is optional
"(\\d+(?:\\.\\d+)?))?" + // Match the second float, because of the ? at the end this part is optional
"\\s*(.*)" + // Match the whitespace after the numbers and put the rest of the chars in the last capturing group
"$"); // Match the end of the string
Matcher m = p.matcher(Text);
if (m.matches()) {
System.out.println(m.group(1));
System.out.println(m.group(2));
System.out.println(m.group(3));
}
}
}
String s = "Mathematics 0.4 - 1.2";
Matcher m = Pattern.compile("(.*?) *([0-9.]+) *(- *([0-9.]*))?").matcher(s);
if(m.matches()){
System.out.println(m.group(1));
System.out.println(m.group(2));
System.out.println(m.group(4));
}
Have you tried this:
String s = "Mathematics 0.4 - 1.2";
pattern = Pattern.compile("([^\d\.\s]+)\b\s+(\d+\.\d+)\D*(\d+\.\d+)?");
matcher = pattern.matcher(s);
if (matcher.matches()) {
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
System.out.println(matcher.group(3));
}
