I have an array:
array1 = [1,2,3,4,5,:value => 'value']
I want to create second array, who is the copy of first array minus :value element (addition: i don't know position of element exactly)
#expected result
array1 = [1,2,3,4,5,:value => 'value']
array2 = [1,2,3,4,5]
#my failure attempt
array2 = array1.delete(:value) # => nil
How can i do this?
You can try this
array2 = array1.reject{|a| a.is_a?(Hash) && a[:value]}
as @mu is too short said this will be safer:
array2 = array1.reject{|a| a.is_a?(Hash) && a.has_key?(:value)}
Or
array2 = array1 - {:value => "value"}
array2 = array1.reject{|a| a.is_a?(Hash) && a[:value]} works great! Thanks!
array1.reject{|a| a.is_a?(Hash) && a.has_key?(:value)} would be safer, you could get an a[:value] that was false or nil after all.If your array has a hash as one of its members (array1 = [1,2,3,4,5,{:value => 'value'}]) and you want to get rid of that member:
array2 = array1.reject{|a| a.is_a?(Hash)} # => array2 will equal [1,2,3,4,5]
If you want to get rid of a member that is a Hash and has a key of :value, you could add that to the reject block:
array2 = array1.reject{|a| a.is_a?(Hash) && a.key?('value')}
delete_if will touch an original Array. You should use reject here
array1 so array1 == array2.Seems easy :
array2 = array1[0..-2]
Or if you aren't sure that the array has a :value key at the end and be sure that only :value is deleted :
array1.delete(:value)
array.delete(:value => 'value') will, but it is not Vladimir wantsAnother clean solution IMHO is to pop if last element is a hash :
array1.pop if array1.last.is_a?(Hash)