Problem with running exe file from c#

Question

When I execute an exe file (PVFProject15.exe), it reads the data from an input file (inputFile.txt) and print the results in another file (outputFile.txt). The exe file works well when I double click it; It opens the console window which stays opened until the output file is created. However, when I run (PVFProject15.exe) from c#, the console window opens and closes very quickly and the output file is never created.

I would really appreciate your help since I have been working to fix this for a whole day and never found the answer. Here is my code below.

private void button1_Click(object sender, EventArgs e)

{
        Process runFortran = new Process();
        try
        {
            runFortran.StartInfo.FileName = "C:\\temp\\trial\\PVFProject15.exe";
            runFortran.Start();
            runFortran.WaitForExit(); 
        }
        catch (Exception exc)
        {
            MessageBox.Show(exc.Message);
        }
    }

Thank you in advance.

Safaa

I've tried your code with notepad, and other console application's I've created, and it seems to work fine. Do you have the code for the PVFProject15.exe? — Mike
– Mike, Commented Jul 14, 2011 at 18:42
You didn't set StartInfo.WorkingDirectory to @"c:\temp\trial". Lots of poorly written programs cannot survive that. — Hans Passant
– Hans Passant, Commented Jul 14, 2011 at 19:17

Mike Mozhaev · Accepted Answer · 2011-07-14 19:19:53Z

1

Probably PVFProject15.exe needs current directory to be set to C:\temp\trial

answered Jul 14, 2011 at 19:19

Mike Mozhaev

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Kirill Polishchuk · Accepted Answer · 2011-07-14 18:59:15Z

0

If PVFProject15.exe writes to file using relative path, look for outputFile.txt in directory from which you start your main program-bootstrapper.

answered Jul 14, 2011 at 18:59

Kirill Polishchuk

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Comments

smartsolution · Accepted Answer · 2013-05-17 07:18:00Z

I also meet with same problem, when I try start some .exe and .hta from my C# based software. I start to looking for solution and answer of Mike Mozhaev get to me right direction. In your code you need to use: StartInfo.WorkingDirectory = Convert.ToString( System.IO.Directory.GetParent(appPath));

So code have to be like this:

 if (File.Exists(appPath))
                {
                    Process runProcess = new Process();
                    runProcess.StartInfo.WorkingDirectory = Convert.ToString( System.IO.Directory.GetParent(appPath));
                    runProcess.StartInfo.UseShellExecute= true;
                    runProcess.StartInfo.FileName = appPath;
                    runProcess.Start();

                }

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