Return min value from array of objects

Question

I have an array of objects. In each object there is a details property (array) with more than one object - for this example I am only showing one.

I am looking for the rating property in each details and looking to find minimum value (in this example 3.1) ... is there a simpler/cleaner way of achieving this?

const ratings = [{ id: 'ABC', details: [{ type: 'VALUE', rating: 9.5 }] }, { id: 'DEF', details: [{ type: 'VALUE', rating: 3.1 }] }, { id: 'GHI', details: [{ type: 'VALUE', rating: 4.5 }] }]
const ids = ['ABC', 'DEF', 'GHI']
const array = []

ids.forEach(element => {
  const valueScore = ratings?.find(r => r.id === element)?.details?.find(c => c.type === 'VALUE')
  if (valueScore.rating) {
    array.push(valueScore.rating)
  }
})
console.log('MIN VALUE', Math.min(...array))

Instead of iterating over the ids and then using find why not just iterate once through ratings, also if your code works and you want feedback/suggestions you might want to look at the code review SE site — depperm
– depperm, Commented Feb 26, 2021 at 16:50

Rajneesh · Accepted Answer · 2021-02-26 17:22:47Z

1

You can use flatMap and then apply math.min to get minimum value:

const ratings = [{ id: 'ABC', details: [{ type: 'VALUE', rating: 9.5 }] }, { id: 'DEF', details: [{ type: 'VALUE', rating: 3.1 },{ type: 'VALUE1', rating: 2.1 }] }, { id: 'GHI', details: [{ type: 'VALUE', rating: 4.5 }] }];

const ids = ['ABC', 'DEF', 'GHI']

console.log(Math.min(...ratings.flatMap(o=>
    ids.includes(o.id) ? o.details.flatMap(p=>
        p.type=='VALUE' ? p.rating : []) : [])));

edited Feb 26, 2021 at 17:22

answered Feb 26, 2021 at 16:53

Rajneesh

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4 Comments

Michael Over a year ago

I am looking for rating of type VALUE though. It's possible there would be another type (e.g. { type: 'TEST', rating: 4 } ... and I don't want to look at that

Michael Over a year ago

Thanks! Also, we need to check that the minimum rating is an id that is found in ids array ... if there is another entry in ratings such as XYZ, this shouldn't be included. can you modify?

Rajneesh Over a year ago

@Michael that was a simple check in flatMap. Updated.

Michael Over a year ago

Thanks so much :) Simple and clean. I always forget about flatMap

Srikar Phani Kumar M · Accepted Answer · 2021-02-26 22:55:35Z

You can do something like this:

Why this method is preferred is, you are running the loop perfectly over each ratings item and also through each details array item.

  ratings = [
    { id: "ABC", details: [{ type: "VALUE", rating: 9.5 }] },
    {
      id: "DEF",
      details: [{ type: "VALUE", rating: 3.1 }, { type: "VALUE1", rating: 2.1 }]
    },
    { id: "GHI", details: [{ type: "VALUE", rating: 4.5 }] }
  ];

  ids = ["ABC", "DEF", "GHI"];
    const detailsRatingArr = [];
    if (ratings.length === ids.length) {
      ratings.forEach(eachRating => {
        ids.forEach(eachId => {
          if (eachRating.id === eachId) {
            eachRating.details.forEach(eachDetail => {
              detailsRatingArr.push(eachDetail.rating);
            });
          }
        });
      });
    }
    console.log("DETAILS ARRAY ==>", detailsRatingArr);
    detailsRatingArr.sort((a, b) => a - b);
    console.log("Minimum Rating ==>", detailsRatingArr[0]);

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