For loop conversion problem from python to PHP

Question

I try to convert the following Python function:

def Sous(dist,d):

    l = len(dist)
    L = [[]]
    for i in range(l):
        K = []
        s = sum(dist[i+1:])
        for p in L:
            q = sum(p)
            m = max(d - q - s, 0)
            M = min(dist[i], d - q)
            for j in range(m, M+1):
                K.append(p + [j])
        L = K
    return L

into a PHP function:

function sous($dist, $d){
    $l = count($dist);
    $L = [[]];
    foreach(range(0,$l) as $i){
        $K = [];
        $s = array_sum(array_slice($dist, $i+1));
        foreach($L as $p){
            $q = array_sum($p);
            $m = max($d-$q-$s, 0);
            $M = min($dist[$i], $d-$q);
            foreach(range($m, $M+1) as $j){
                $K[] = $p+$j;
            }
        }
        $L = $K;
    }
    return $L;
}

And when I test it:

var_dump(sous([3,2,2,1,1,0], 2));

I get the error:

Uncaught Error: Unsupported operand types

for the line

$K[] = $p+$j;

And I don't know how to solve it, do you have any ideas?

Looks like $p is an array, and (in PHP) you can't just add a number to array with +. — Nigel Ren
– Nigel Ren, Commented Jan 16, 2021 at 9:42
i think the problem is that [j] doesn't mean $j in PHP, but what does it mean ? — Romain Charles
– Romain Charles, Commented Jan 16, 2021 at 9:54

mrbm · Accepted Answer · 2021-01-16 09:53:52Z

2

Python's range(n) returns an array from 0 to n-1 while PHP's range($n, $m) returns an array from $n to $m, so you have to use range(0, $l -1) there.

Also K.append(p+[j]) should be converted to $K[] = $p+[$j]; since $j is not an array.

The following function should work:

function sous($dist, $d){
    $l = count($dist);
    $L = [[]];
    foreach(range(0,$l - 1) as $i){
        $K = [];
        $s = array_sum(array_slice($dist, $i+1));
        foreach($L as $p){
            $q = array_sum($p);
            $m = max($d-$q-$s, 0);
            $M = min($dist[$i], $d-$q);
            foreach(range($m, $M+1) as $j){
                $K[] = $p+[$j];
            }
        }
        $L = $K;
    }
    return $L;
}

answered Jan 16, 2021 at 9:53

mrbm

2,19412 silver badges11 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

For loop conversion problem from python to PHP

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related