JS pass array values as separate arguments

Question

I have a CSV file of some data and for each line, I split it by the comma to get an array vals.

Now I want to pass vals into a function, but "flatten" it (without changing the function because it is used elsewhere)

function foo(x, y, z) {
     return x*y*z:
}
    
var vals = [1, 3, 4];
//want a shortcut to this (this would be a nightmare with like 20 values)
foo(vals[0], vals[1], vals[2]);

Edit:
Sorry, kind of left out a big detail. I only want part of the array, like the first 10 elements of a 12 element array. Any shortcut for this?

In JavaScript, you don't need to specify var for the arguments. function foo(x, y, z) works fine. — Not A Robot
– Not A Robot, Commented Dec 30, 2020 at 7:21

Prashant Prabhakar Singh · Accepted Answer · 2020-12-30 07:22:52Z

4

Use Spread operator; if you are using es6.

var vals = [1,2,34,5]
foo(...vals)

Or you could also use apply

function foo(a,b,c,d,e) {
  console.log(a,b,c,d,e)
}
var vals = [1,2,3,4,5]
foo.apply(null, vals)

answered Dec 30, 2020 at 7:22

Prashant Prabhakar Singh

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Comments

kennysliding · Accepted Answer · 2020-12-30 07:23:55Z

0

first you don't need var in the parameters,

second, you may use the spread operator

function foo(x, y, z) {
  return x * y * z;
}
var vals = [1, 3, 4];
console.log(foo(...vals));

reference: spread operator

answered Dec 30, 2020 at 7:23

kennysliding

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