ruby array split at String

Question

I have an array that looks like this...

array=["cab 3 > ", #<...>, #<...>, #<...>, "cab 2 > ", #<...>, #<...>, "cab 1 > ", #<...>]

I'd like to split it at every String to get this...

array=[["cab 3 > ", #<...>, #<...>, #<...>], ["cab 2 > ", #<...>, #<...>], ["cab 1 > ", #<...>]]

I tried... but can't figure it out

array.group_by{|name| p name.split(/""/)} 
array.group_by{|name| p name.split(/\"\"/)} 
array.group_by{|name| p name.split(String)}

Jörg W Mittag · Accepted Answer · 2020-12-11 16:52:39Z

4

So, you want to create a new slice of the array before every String.

This can be achieved using the Enumerable#slice_before method:

array.slice_before(String)

This will return an Enumerator of the form you desire. If you absolutely need an Array, then you can use the Enumerable#to_a method:

array.slice_before(String).to_a
#=> [["cab 3 > ", 1, 1, 1], ["cab 2 > ", 1, 1], ["cab 1 > ", 1]]

answered Dec 11, 2020 at 16:52

Jörg W Mittag

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2 Comments

JoMojo Over a year ago

The second option did exactly what I needed... thanks

Cary Swoveland Over a year ago

To my surprise, you could fine-tune this by writing r = /\Acab \d+ > \z/; array.slice_before(r).to_a => [["cab 3 > ", 1, 1, 1], ["cab 2 > ", "cat", 1], ["cab 1 > ", 1]]. This works because r === 1 #=> false.

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