Changing url in requests (Python)

Question

I got some strange error with requests. Code is:

    key = key.replace(" ", "_")
    print(key)
    url = f"https://pl.wikipedia.org/api/rest_v1/page/summary/{key}"
    print(url)
    summary = http.get(url)
    summary = summary.json()
    print(summary)

The output from prints:

A

https://pl.wikipedia.org/api/rest_v1/page/summary/A


{'type': 'https://mediawiki.org/wiki/HyperSwitch/errors/bad_request', 'method': 'get', 'detail': 'title-invalid-characters', 'uri': '/pl.wikipedia.org/v1/page/summary/A%0A'}

The site returns an error with uri that is different from the url variable. Why? Anyway, I cannot access it. And I see A is changing to A%0A.

What's the content of key at the beginning?

jizhihaoSAMA
– jizhihaoSAMA

2020-11-20 08:38:00 +00:00
Commented Nov 20, 2020 at 8:38 — jizhihaoSAMA
– jizhihaoSAMA, Commented Nov 20, 2020 at 8:38
It is user-defined.

NORXND
– NORXND

2020-11-20 10:15:23 +00:00
Commented Nov 20, 2020 at 10:15 — NORXND
– NORXND, Commented Nov 20, 2020 at 10:15

NavaneethaKrishnan · Accepted Answer · 2021-01-03 14:17:41Z

4

Can you see an empty line in the output (2nd line) after the A. That is the problem. A line feed is there at the end of A.. (A\n). You have to remove the \n.

Use key.strip(). This will remove all leading and trailing whitespace.

And URL encoding for LF - line feed (\n) is %0A. That's why your URL changed to A + %0A.

edited Jan 3, 2021 at 14:17

answered Nov 20, 2020 at 8:49

NavaneethaKrishnan

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