Check if array has same values as other array [duplicate]

Question

I am trying to filter my entites by tags array, that can look like this:

const tags = ["tag1", "tag2"];

Every entity has property tags, that can have existing tags, for example:

["tag1", "tag2", "tag3"];

Or:

["tag1", "tag2"];

I need to compare if the tags array and the tags array of entity has the same values. So far I have tried this code, but it returns an entity even if the two arrays dont have the same values (I'm guessing the includes() function is to blame).

tags.every((tag: any) => doc.tags.includes(tag));

Any ideas how can I check if the arrays have the same values?

Thank you in advance.

But really, you need to decide which array is the one that has to have all the values (i.e., which gets the every and which gets the includes. — Heretic Monkey
– Heretic Monkey, Commented Oct 27, 2020 at 13:29
@known-as-bmf not necessary in the same place but same values and same length — AdamSulc
– AdamSulc, Commented Oct 27, 2020 at 13:34

Aadil Mehraj · Accepted Answer · 2020-10-27 13:28:47Z

2

You can also compare the length as well

tags.every((tag: any) => doc.tags.includes(tag)) && tags.length === doc.tags.length;

answered Oct 27, 2020 at 13:28

Aadil Mehraj

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3 Comments

AdamSulc Over a year ago

I thought that there is some more elegant way to deal with this, but the length check works.

known-as-bmf Over a year ago

You should check the length first (for short circuiting) and this wont work in a scenario like this: ['a','b','a'] and ['a','b','c'].

Aadil Mehraj Over a year ago

Only applicable in case of duplicates, in that case first need to remove dups ones then made the comparison

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