python:extract certain part of string

Question

I have a string from which I would like to extract certain part. The string looks like :

 E:/test/my_code/content/dir/disp_temp_2.hgx

This is a path on a machine for a specific file with extension hgx

I would exactly like to capture "disp_temp_2". The problem is that I used strip function, does not work for me correctly as there are many '/'. Another problem is that, that the above location will change always on the computer.

Is there any method so that I can capture the exact string between the last '/' and '.'

My code looks like:

path = path.split('.')

.. now I cannot split based on the last '/'.

Any ideas how to do this?

Thanks

jfocht · Accepted Answer · 2011-06-23 13:54:47Z

6

Use the os.path module:

import os.path
filename = "E:/test/my_code/content/dir/disp_temp_2.hgx"
name = os.path.basename(filename).split('.')[0]

answered Jun 23, 2011 at 13:54

jfocht

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2 Comments

jfocht Over a year ago

Depends on what the user wants. The code above will turn something like foo.tar.gz into foo. This seems like the desired behavior. If someone has multiple dots in a filename like my.cool.file.txt then the convention becomes ambiguous and cannot be parsed without domain specific knowledge.

user741592 Over a year ago

Thanks this works perfect for me. The file name that we has always one dot. That is before the extension.

bgporter · Accepted Answer · 2011-06-23 13:58:23Z

3

Python comes with the os.path module, which gives you much better tools for handling paths and filenames:

>>> import os.path
>>> p = "E:/test/my_code/content/dir/disp_temp_2.hgx"
>>> head, tail = os.path.split(p)
>>> tail
'disp_temp_2.hgx'
>>> os.path.splitext(tail)
('disp_temp_2', '.hgx')

answered Jun 23, 2011 at 13:58

bgporter

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Comments

Roman Bodnarchuk · Accepted Answer · 2011-06-23 14:13:14Z

1

Standard libs are cool:

>>> from os import path
>>> f = "E:/test/my_code/content/dir/disp_temp_2.hgx"
>>> path.split(f)[1].rsplit('.', 1)[0]
'disp_temp_2'

edited Jun 23, 2011 at 14:13

answered Jun 23, 2011 at 13:54

Roman Bodnarchuk

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Comments

Sahas · Accepted Answer · 2011-06-23 13:54:55Z

0

Try this:

path=path.rsplit('/',1)[1].split('.')[0]

answered Jun 23, 2011 at 13:54

Sahas

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Comments

dave · Accepted Answer · 2011-06-23 13:55:50Z

0

path = path.split('/')[-1].split('.')[0] works.

answered Jun 23, 2011 at 13:55

dave

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Comments

JMax · Accepted Answer · 2011-06-23 13:56:01Z

0

You can use the split on the other part :

path = path.split('/')[-1].split('.')[0]

answered Jun 23, 2011 at 13:56

JMax

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