Concatenation in Python, concatenating lists and strings

Question

i'm not sure if this is the correct syntax to do this, but i want to print out a specific element in a list.

user,activity,data=readfile('data.txt')
kclust,clusters=kcluster(data,k=3)
for i in range(len(kclust)):
    print "Cluster %d: ??" % (i+1,clusters[i])
    print [[userobjectIds[r] for r in kclust[i]][:3]]
    print

the '??' is where i've tried %d and %o but get: "TypeError:%o format:a number is required, not list"

Are you expecting to print a number? You can verify that clusters[i] actually contains a number (or whatever type you intended) by reading the output of print type(clusters[i]). — Heatsink
– Heatsink, Commented Jun 22, 2011 at 19:51
Any time you're doing for i in range(len(foo)): you're probably doing it wrong. Do instead for i, sublist in kclust.enumerate(): and the list comp can be [userobjectIds[v] for v in sublist[:3]] — Daenyth
– Daenyth, Commented Jun 22, 2011 at 20:03
@Daenyth: Should be enumerate(kclust) (unless klust is something different than a list). But this is definitely the correct approach. — Felix Kling
– Felix Kling, Commented Jun 22, 2011 at 20:12

Felix Kling · Accepted Answer · 2011-06-22 19:50:51Z

5

You can use %r:

'r': String (converts any Python object using repr()).

print "Cluster %d: %r" % (i+1,clusters[i])

answered Jun 22, 2011 at 19:50

Felix Kling

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Charles Brunet · Accepted Answer · 2011-06-22 19:51:40Z

0

I don't know about kcluster function, but it seems it returns a list, not a number. Alternatively, you could try:

print "Cluster %d:"%(i+1), clusters[i]

answered Jun 22, 2011 at 19:51

Charles Brunet

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