How can I check if user input is in a random string from a list?

Question

I am trying to program hangman. I am quite new and am wondering something. I already figured this out

 x = "Hello World"
print(x[2])
print(x[6])
print(x[10])

The output is

l
W
d

I am wondering if i can write this:

import random
list = ["Hi","Hello","Hi wrld","Hello world"]
chosen = list(random.randint(1,4)
nr_of_letters = len(chosen)
# j is the letter the user guesses
j = input()
if j == chosen[0,nr_of_letters]:
   print("something")
else:
   print("something else")

The error info I get is that the number has to be an integer. If I try writing it differently I have 2 options.

#the first option is :
j = int(input ())
#the second option is:
if j == chosen[0,int(nr_of_letters)]:

neither of them work. Please how can I write that correctly.

Try: chosen = list[random.randint(0,3)]

Mike67
– Mike67

2020-10-09 20:21:52 +00:00
Commented Oct 9, 2020 at 20:21 — Mike67
– Mike67, Commented Oct 9, 2020 at 20:21

Rolv Apneseth · Accepted Answer · 2020-10-09 20:27:54Z

1

So first, to choose a random word from a list:

import random
words = ["Hi","Hello","Hi wrld","Hello world"]
chosen = random.choice(words)
# Chosen will now be one of the words in the list

Since you're trying to code hangman I assume you know you'll need a while loop to allow the user to keep giving input so I'll just work with what you've given here as an example. So for checking if they entered a correct letter:

j = input()
if j in chosen:
    print("something")
else:
    print("something else")

Is that ok?

answered Oct 9, 2020 at 20:27

Rolv Apneseth

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