Javascript Uncaught ReferenceError: parameter is not defined

Question

I have some Javascript code:

function addRow(tableID, rowId) {
var table = document.getElementById(tableID);
var rowPosition = document.getElementById(rowID).rowIndex;
//etc.
}

But this throws a Javascript error

"Uncaught ReferenceError: rowID is not defined"

Though looking on Firebug, I can see that the functions receives a correct row identifier, but once the code reaches the second line inside the function the parameter rowID seems unknown.

Can anyone help?

Ateş Göral · Accepted Answer · 2011-06-17 13:41:13Z

9

JavaScript is case-sensitive. You've used rowId as the argument name (small "d") while inside the function you have rowID (capital "D"). Change the argument to rowID to fix the issue.

answered Jun 17, 2011 at 13:41

Ateş Göral

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Jivings · Accepted Answer · 2011-06-17 13:41:39Z

4

You're passing the parameter rowId, but referencing it rowID. Variable names are case sensitive, they both need to be the same.

answered Jun 17, 2011 at 13:41

Jivings

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