How to sort output of 2 same array data

Question

I have :

1 array input (A)
1 array (B) for compare (comparing A to B)
1 array output

I want the data to be like this :
    data array A    data array B      output array
    Alpha           Alpha             Alpha*
    Delta           Beta              Beta
    Fanta           Charlie           Charlie    
                    Delta             Delta*
                    Echo              Echo
                    Fanta             Fanta*

What I want is, whenever there is a same data in array A and B, "the data" marked by *. I'm sorry if my english is not easy to understand.

Thanks in advance

What you want in this do you want to merge the two arrays with same element appearing once ? list(set(arr1 + arr2)) — Deepak Tripathi
– Deepak Tripathi, Commented Aug 31, 2020 at 6:46
Please include what you have tried already to give us a start. SO is not a code writing service that will provide code from scratch. — Jeff
– Jeff, Commented Aug 31, 2020 at 6:47
The question is not clear to me: do you want the output array to be a union of the input arrays, but the items that show up in the intersection to be modified to have a '*' concatenated to them ? — user5117733
– user5117733, Commented Aug 31, 2020 at 6:47
I'm sorry if the question is not clear, I have modified my question. — infdefurlong
– infdefurlong, Commented Aug 31, 2020 at 6:59

Andrej Kesely · Accepted Answer · 2020-08-31 07:04:06Z

1

I hope I understood your question right: you want to merge two arrays, and each element should appear only once (assuming sorted lists a and b):

from heapq import merge
from itertools import groupby

a = ['Alpha', 'Delta', 'Fanta']
b = ['Alpha', 'Beta', 'Charlie', 'Delta', 'Echo']

c = [v for v, _ in groupby(merge(a, b))]

print(c)

Prints:

['Alpha', 'Beta', 'Charlie', 'Delta', 'Echo', 'Fanta']

EDIT: To mark duplicate elements with *, you can do:

from heapq import merge
from itertools import groupby

# assuming sorted `a` and `b`:
a = ['Alpha', 'Delta', 'Fanta']
b = ['Alpha', 'Beta', 'Charlie', 'Delta', 'Echo', 'Fanta']

c = ['{}*'.format(v) if len(list(g)) > 1 else v for v, g in groupby(merge(a, b))]

print(c)

Prints:

['Alpha*', 'Beta', 'Charlie', 'Delta*', 'Echo', 'Fanta*']

edited Aug 31, 2020 at 7:04

answered Aug 31, 2020 at 6:49

Andrej Kesely

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6 Comments

Deepak Tripathi Over a year ago

why not use list(set(a+b))

Andrej Kesely Over a year ago

@DeepakTripathi set() is unordered structure and I think OP wants sorted output.

vgeorge Over a year ago

@AndrejKesely i run your code with a = ['Alpha', 'Delta', 'Fanta','Alpha'] (note 2 'alpha' in the array a) so it produce output as ['Alpha', 'Beta', 'Charlie', 'Delta', 'Echo', 'Fanta', 'Alpha']

Andrej Kesely Over a year ago

@vgeorge I assumed sorted lists a and b. If they aren't sorted, you need to do a = sorted(a) and for b too before merge.

infdefurlong Over a year ago

yea, i want a sorted output, and if there is a same data in array A and B, "the data" marked by *.

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