I have a 3D numpy array of the shape (1, 60, 1). Now I need to remove the first value of the second dimension and instead append a new value at the end.
If it was a list, the code would look somewhat like this:
x = [1, 2, 3, 4]
x = x[1:]
x.append(5)
resulting in this list: [2, 3, 4, 5]
What would be the easiest way to do this with numpy?
I have basically never really worked with numpy before, so that's probably a pretty trivial problem, but thanks for your help!
import numpy as np
arr = np.arange(60) #creating a nd array with 60 values
arr = arr.reshape(1,60,1) # shaping it as mentiond in question
arr = np.roll(arr, -1) # use np.roll to circulate the array left or right (-1 is 1 step to the left)
#Now your last value is in the second last position, the second last value in the third last pos and so on (Your first value moves to the last position)
arr[:,-1,:] = 1000 # index the last location and add the values you want
print(arr)
