I need to store a function alongside with its parameters on an object, that is to say something like this:
function myFunction(params) {
console.log('Params',params);
}
const obj = {method: myFunction, params: [params]};
how can I construct this function and its parameters again in order to execute it from what I have in obj?
I'm not sure what you mean by "construct," but you can call it like this:
obj.method(obj.params);
Live Example:
function myFunction(params) {
console.log('Params',params);
}
const obj = {method: myFunction, params: ["example"]};
// Note: Fixed typo −−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−^
obj.method(obj.params); // Shows: Params example
more beautiful but requires ES6
const myFunction = (params) => {
console.log('Params',params);
}
Now you can put it in your object how you did. you can execute it by using
obj.method(obj.params)
How about using a closure to store the params and then returning another function? Then you wouold not have to store them within an object, like so:
function createClosure(params) {
return function {
console.log(`Params: ${params}`);
}
}
or in ES6 Syntax:
const createClosure = (params) => () => {
console.log(`Params: ${params}`);
};
In both cases, you could store and call the function like this:
const myClosure = createClosure(params);
// then somewhere else
myClosure(); // prints params
)(closing parenthesis) just before the;at the end ofconst obj = {method: myFunction, params: [params]);should be a}(closing curly brace).