How to create url with parameters in get request laravel

Question

I would like to create an url as shown below

/domain/url=cloud_hosting&name=cloud_hosting

this is the href url that I use in my blade

<a href="{{ url('domain', ['url' => Request::segment(2), 'name' => $page_name]) }}">continue</a>

but that href url is generating different route

/domain/cloud_hosting/cloud_hosting

I have tried this one:

<a href="{{ route('domain') }}?url={{ Request::segment(2) }}&name={{ $page_name }}">Continue</a>

and that's working fine. But is there any other way which is nice and beautifull? Thank you

route('domain', [ 'url' => Request::segment(2), 'name' => $page_name ]) might also work — apokryfos
– apokryfos, Commented Aug 8, 2020 at 13:51
@NaveedAli. Not, it's just normal route defined on web.php Route::match(['get', 'post'], 'domain', 'Customer\DomainConfigurationControllers@index'); — Maryadi Poipo
– Maryadi Poipo, Commented Aug 8, 2020 at 13:56
@apokryfos, that's not what I wanted because it will be generating /domain/cloud_hosting/cloud_hosting — Maryadi Poipo
– Maryadi Poipo, Commented Aug 8, 2020 at 13:56

Naveed Ali · Accepted Answer · 2020-08-08 14:11:37Z

1

you can do something like below. simply make a get request as in Web.php

Route::get('domain')

and can use it like below and can pass multiple query strings:

<a href="{{ url('domain?url='.Request::segment(2).'&name='.$page_name) }}">continue</a>

answered Aug 8, 2020 at 14:11

Naveed Ali

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Comments

jewishmoses · Accepted Answer · 2020-08-08 14:47:43Z

1

You can also use the query method:

url('domain', Arr::query(['url' => request()->segment(2), 'name' => $page_name]))

// /domain/url=cloud_hosting&name=cloud_hosting

answered Aug 8, 2020 at 14:47

jewishmoses

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