How do I make a function that takes an input, for example 13, and then executes all the functions in the array on that input and returns the output, which would be 4 in this case
array = [
function(a){ return a * 2 },
function(a){ return a + 1000},
function(a){ return a % 7 }
]
function f(array){
console.log(array);
}
As Dave replied in the question, you could use reduce to make this happen:
const runFunctionSequence = (sequence, input) => sequence.reduce((accumulatedOutput, fun) => fun(accumulatedOutput), input);
const arr = [
function(a){ return a * 2 },
function(a){ return a + 1000},
function(a){ return a % 7 }
];
console.log(runFunctionSequence(arr, 13)); // -> 4You want to run a number and each result through series of functions which are stored in an array.
arr = [
function(a){ return a * 2 },
function(a){ return a + 1000},
function(a){ return a % 7 }
]
function runAll(input){
let output = input;
for (let f of arr) {
output = f(output)
}
return output;
}
console.log(runAll(13)) //4
if (a === 13) return 4;but I can't figure how you want to fit an array into this, and even less that array of functions you have. Mind rephrasing a bit?array.reduce((ret, fn) => fn(ret), 13)will output4