How to retrieve partial text from a text node using Selenium and Python

Question

I want to get only " text ... " not using .split() or index slicing

HTML:

<a class="call_recipe" href="/recipes/2913">
      " text ... "
      <strong> something~ </strong>
    </a>

HTML Snapshot:

undetected Selenium · Accepted Answer · 2021-01-29 20:57:11Z

To print text ... you have to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

Using CSS_SELECTOR, childNodes and strip():

print(driver.execute_script('return arguments[0].firstChild.textContent;', WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a.call_recipe[href^='/recipes']")))).strip())

Using XPATH, get_attribute() and splitlines():

print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[@class='call_recipe' and starts-with(@href, '/recipes')]"))).get_attribute("innerHTML").splitlines()[1])

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

References

You can find a couple of relevant detailed discussions in:

David Jay Brady · Accepted Answer · 2020-06-18 08:50:12Z

0

driver.find_element_by_class_name("call_recipe").text

I think this is what you're after.

How to get text with selenium web driver in python

answered Jun 18, 2020 at 8:50

David Jay Brady

1,20410 silver badges22 bronze badges

Comments

Richardson · Accepted Answer · 2020-06-18 08:53:15Z

0

you can utilize the

 "find_element_by_class_name("some_text").getText()"

or to better match the text you can use

"driver.find_element_by_xpath("..").text"

Hope this is helpful

answered Jun 18, 2020 at 8:53

Richardson

1249 bronze badges

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