How to pick a random string from random array

Question

I've picked a random array of 10 from 28, now I am trying to pick a random 1 from the 10 but can't seem to figure out how. Here's my code:

            Random rand = new Random();



        int[] array = new int[10];
        int count = 0;


        for (int i = 0; i < array.Length; i++)
        {
            int final = rand.Next(28);
            while (final == array[0] || final == array[1] || final == array[2] || final == array[3] || final == array[4] || final == array[5] || final == array[6] || final == array[7] || final == array[8] || final == array[9])
            {
                final = rand.Next(10);

            }
            array[i] = final;
            count++;
            Console.WriteLine($"#{count} player {array[i]}");
            string finalists = names[final].firstname.ToString();
            Console.WriteLine($"Finalist: {finalists}");
            Thread.Sleep(2000);

        }

thanks so much for any help

Did you try something like array[rand.Next(10)] to get your final random selection from the original random ten? Btw a more effective way of getting your ten numbers is probably to generate a list of all numbers between 0-28, shuffle the list and then take the first ten items. See: stackoverflow.com/q/273313/491907 — pinkfloydx33
– pinkfloydx33, Commented Jun 15, 2020 at 0:18
you can also order by Guid values and select the first 10 elements. OrderBy Guid.NewId() — SteinTech
– SteinTech, Commented Jun 15, 2020 at 0:21
@SteinTheRuler - Don't use Guids for randomness. They are only guaranteed to be unique, not random. — Enigmativity
– Enigmativity, Commented Jun 15, 2020 at 0:27
@Enigmativity you can use Guid for random if it gives you an acceptable result. and you can also use other elements. — SteinTech
– SteinTech, Commented Jun 15, 2020 at 2:29
@SteinTheRuler - Sure, but you didn't make that disclaimer on your comment. And what do you mean by "you can also use other elements"? — Enigmativity
– Enigmativity, Commented Jun 15, 2020 at 2:38

Enigmativity · Accepted Answer · 2020-06-15 00:33:18Z

1

Does this work for you?

// make an array of 28 names
string[] names =
    Enumerable
        .Range(0, 28)
        .Select(x => $"Person {x + 1}")
        .ToArray();

Random rand = new Random();

// select 10 at random
string[] random10 =
    names
        .OrderBy(x => rand.Next())
        .Take(10)
        .ToArray();

//pick one at random from the 10 selected at random
string finalist = random10[rand.Next(random10.Length)];

answered Jun 15, 2020 at 0:33

Enigmativity

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