Python lambda sorted function how to code it properly?

Question

I have a list of all countries in the world with its population e.g.

Countries = [("argentina", 124854), ("brazil",568854)]

The first value is a string=country the second is integer = population

The task is sort the list by it second value by using reverse true when sorted, I have managed to do it by the string first value country in analphabetic order ASC and DESC but I don't know how to write the code to sort by population in from the largest to smallest population?

pop lambda country:country[1]
countries.sort(key=pop, reverse=True)
Countries

This code doesn't work as expected.

"This code doesn't work as expected." What happens instead?

Perry
– Perry

2020-06-15 00:56:33 +00:00
Commented Jun 15, 2020 at 0:56 — Perry
– Perry, Commented Jun 15, 2020 at 0:56

Andrej Kesely · Accepted Answer · 2020-06-14 21:54:03Z

1

Countries = [("argentina", 124854), ("brazil",568854)]

print(sorted(Countries, key=lambda k: k[1], reverse=True))

Prints:

[('brazil', 568854), ('argentina', 124854)]

Or:

print(sorted(Countries, key=lambda k: -k[1]))

answered Jun 14, 2020 at 21:54

Andrej Kesely

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